Saturday, April 9, 2011

Math trick 4 = 5

Let
A=4,
B=5,
C=1

C=(B-A)
C(B-A)=(B-A)^2
CB-CA=B^2-2AB+A^2
CB-CA-A^2=B^2-2AB
AB+CB-CA-A^2=B^2-AB
AB-CA-A^2=B^2-CB-AB
A(B-C-A)=B(B-C-A)
A=B
4=5
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1 comment:

  1. Books......April 9, 2011 at 3:52 AM

    hey friend, in this trick you are cancelling (B-C-A) in the line A(B-C-A)=B(B-C-A), which is not possible because it is in the form of 0/0. So your trick is not correct. It is impossible to prove 4=5.

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